Which of the following isomerism is not possi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $(i) \ Pt(SCN)_2 \cdot 3PEt_3$ is a square planar complex $(Pt^{II})$,which generally does not exhibit optical isomerism.$(ii) \ CoBr \cdot SO_4 \

Vedclass · Accepted Answer

Optical

Vedclass · Answer

(A) $(i) \ Pt(SCN)_2 \cdot 3PEt_3$ is a square planar complex $(Pt^{II})$,which generally does not exhibit optical isomerism.$(ii) \ CoBr \cdot SO_4 \cdot 5NH_3$ can show ionisation isomerism (exchange of $Br^-$ and $SO_4^{2-}$).$(iii) \ FeCl_3 \cdot 6H_2O$ can show hydrate isomerism (exchange of $H_2O$ and $Cl^-$).Linkage isomerism is possible in $(i)$ due to the ambidentate ligand $SCN^-$.Therefore,optical isomerism is the type that is not universally possible across these specific complexes.

Which of the following isomerism is not possible for complexes having molecular formulas:
$(i) \ Pt(SCN)_2 \cdot 3PEt_3$
$(ii) \ CoBr \cdot SO_4 \cdot 5NH_3$
$(iii) \ FeCl_3 \cdot 6H_2O$

Similar Questions

The magnetic moment of a transition element is $\sqrt{15} \, B.M.$ Determine the number of unpaired electrons present in it.

The complex having the highest spin-only magnetic moment is

Provide evidence that $[Co(NH_3)_5Cl]SO_4$ and $[Co(NH_3)_5SO_4]Cl$ are ionization isomers.

The 'spin only' magnetic moment value of $MO_4^{2-}$ is . . . . . $BM$. (Where $M$ is a metal having least metallic radii among $Sc, Ti, V, Cr, Mn$ and $Zn$).
(Given atomic number: $Sc=21, Ti=22, V=23, Cr=24, Mn=25$ and $Zn=30$)

Which of the following is not correctly matched?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which of the following isomerism is not possible for complexes having molecular formulas:$(i) \ Pt(SCN)_2 \cdot 3PEt_3$$(ii) \ CoBr \cdot SO_4 \cdot 5NH_3$$(iii) \ FeCl_3 \cdot 6H_2O$